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Mar 9, 2020 at 7:27 comment added Eltea Trialdi Ups, my bad. Sorry. Both of you are right. Thanks for the correction.🙏
Mar 7, 2020 at 22:57 comment added Herr K. The second method would give $\frac12(9-3)3=9$, same as first.
Mar 7, 2020 at 18:58 comment added Giskard "Both MC and AVC are linear curves emanating from 0." This is not true, from your formula $MC$ clearly starts at the height 3. This is relevant because "1/2.MC.Q" calculates the area of a triangle with height $MC$ and base $Q$, but in your example the area under the $MC$ is not a triangle, as it does not start from 0.
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Mar 10, 2020 at 2:34
Mar 7, 2020 at 6:30 review First posts
Mar 7, 2020 at 22:57
Mar 7, 2020 at 6:29 history answered Eltea Trialdi CC BY-SA 4.0