Timeline for Micro: proving that cost minimizing input vector for producing y cannot produce more than y
Current License: CC BY-SA 4.0
7 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Jul 14, 2021 at 16:19 | vote | accept | Dayne | ||
| Jul 13, 2021 at 10:05 | comment | added | Dayne | @tdm: I have attempted the answer with the additional assumption of ‘inaction’ along with assumption 2 in your answer (relaxing assumption 1 in the process). | |
| Jul 13, 2021 at 8:21 | comment | added | VARulle | Didn't work through the proof, but some ' seems to be missing at the end. | |
| Jul 13, 2021 at 4:56 | comment | added | tdm | @Dayne I'm not convinced, but please try if you think it works. | |
| Jul 12, 2021 at 18:01 | comment | added | Dayne | Also I think rather than assuming interior condition in assumption 1, we can add in assumption 2 that $0 \in V(0)$. That would suffice. | |
| Jul 12, 2021 at 17:40 | comment | added | Dayne | :). So first, I didn’t mention monotonicity because i mentioned that V(y) is the set to at least produce y. So this should capture assumption 1. And as a nice surprise, just before you posted the answer I commented assumption 2. Thanks so much with assumption 2 I also proved this way :) | |
| Jul 12, 2021 at 17:33 | history | answered | tdm | CC BY-SA 4.0 |