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Oct 13, 2023 at 0:49 comment added Paul Huang Sorry for the confusion. I just mean that I happened to prove the "If NOT $xA\ge 0$ then NO mixed strategy NE" case, but just don't know how to deal with prove the original statement.
Oct 12, 2023 at 14:49 answer added VARulle timeline score: 3
Oct 12, 2023 at 13:20 comment added Giskard You stipulate "$\exists x\in R_+^I$ such that $xA\ge0$" but then go on to write "if $xA$ always has negative element(s)". Don't these two contradict?
Oct 12, 2023 at 12:00 history edited Giskard
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Oct 12, 2023 at 4:00 history asked Paul Huang CC BY-SA 4.0