Timeline for Calculation of simple elasticity problem
Current License: CC BY-SA 4.0
3 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Nov 18, 2023 at 5:24 | comment | added | guest | @ EB3112 It is enough to understand that $0.2=\frac{1}{5}$. | |
| Nov 17, 2023 at 14:39 | comment | added | EB3112 | Hi @tdm. For my own benefit, could you include any additional steps in going from: $$2i_1^{-0.2} = i_0^{-0.2}$$ to $$\frac{i_1}{i_0} = 2^5$$. Would be appreciated. | |
| Nov 16, 2023 at 6:45 | history | answered | tdm | CC BY-SA 4.0 |