My professor gave us the following problem, but it uses a notation/syntax I haven't seen before $(q_{luke} = max \{ \dots \})$. She hasn't explained it or introduced it to us prior to this.

What does this mean? I assume it must be somehow translatable into $y=mx+b$ form given the context of the problem, but I'm not sure how. Thanks!

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    $\begingroup$ It means the maximum of $90-4p$ and $0$; that is, if $90-4p$ becomes negative (due to $p$ large), then $q_\text{lea}=0$ (for all $p$ such that $90-4p<0$). $\endgroup$ – Herr K. Jan 26 '16 at 7:43
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    $\begingroup$ This is more of a comment than an answer. If you write this up as an answer instead of a comment Jay can accept it and you'll get points for your answer. $\endgroup$ – BKay Jan 26 '16 at 15:02
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    $\begingroup$ Except that it is more of an answer than a comment. :-P $\endgroup$ – HRSE Jan 27 '16 at 6:30
  • $\begingroup$ So the professor is eliminating any negative values which are unplottable on the graph and theoretically shouldn't happen. $\endgroup$ – chicks Jan 28 '16 at 21:14

max {a, b, c} means the highest of these elements.

For example, if "b" is higher than a and c, then max {a, b, c} = b

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    $\begingroup$ Worth noting is that there is also a function, $\min \{\}$ where you take the lowest, or minimum, of the elements in the bracket. $\endgroup$ – majmun Jan 28 '16 at 1:25

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