If $f:\mathbb{R}^n \to \mathbb{R} $ is twice continuously differentiable, has a non-negative gradient, and is supermodular, and $g: \mathbb{R} \to \mathbb{R}$ is twice continuously differentiable and convex, then $g(f(x))$ is increasing and supermodular
To show increasing I think we can just show $\displaystyle \frac{d}{dx} g(f(x)) > 0$
$$ \displaystyle \frac{d}{dx} g(f(x) = g'(f(x)) f'(x) $$
Since $f(x)$ has a non-negative gradient $f'(x) \geq 0$, but I'm not sure how to show $g'(f(x)) > 0$ as given convex tells us $g''(x) > 0$
For supermodularity, let $l, l' \in \mathbb{R}^n$; $g(f(x))$ will be supermodular if the following inequality holds:
$$ \displaystyle (g \circ f)(l \vee l') + (g \circ f)(l \wedge l') \geq (g \circ f)(l) + (g \circ f)(l') $$
I think if we had $l_i \leq l_i', \; \forall i$, then we will have equality as $(g \circ f)(l \vee l') = (g \circ f)(l') $ and $ (g \circ f)(l \wedge l') = (g \circ f)(l)$, but don't know what to do for the other cases.