# Oddness of equilibrium points

I have seen that generically any finite games have odd number of equilibria. So for $2\times 2$ games can we say that generically they must have $3$ equilibria? If not can you give an example of games which have $5$ or $7$ equilibria? Many thanks!

It depends on what you mean by generically. The Prisoner's Dilemma has exactly one equilibrium. If you generate the payoffs in your $2 \times 2$ game by drawing payoffs from continuous i.i.d.'s then there is a non-zero probability (seems to me that the exact number is 25%) that you will get a game similar to the Prisoner's Dilemma, i.e. a game with strictly dominant strategies for both players.
You can also have a game with an infinite number of equilibria. (E.g. a $2 \times 2$ game with all zeros.)
However if the number of equilibria is finite you cannot have more than three in a $2 \times 2$ game.