4
$\begingroup$

I need to verify that $u(x,y)=x^{1/3}y^{1/3}$ represents the same preferences as $v(x,y)=x^3y^3$. Obviously these are completely different functions with different derivatives, so what am I comparing? What makes 2 utility functions represent the same preferences?

$\endgroup$
3
  • 3
    $\begingroup$ If you can find a monotonically increasing continuous transformation that turns one into the other, then they have the same preferences. Can you find that? $\endgroup$
    – VCG
    Commented Sep 11, 2016 at 22:39
  • 4
    $\begingroup$ @VCG Why are you hating on non-continuous monotonically increasing transformations bro? $\endgroup$
    – Giskard
    Commented Sep 11, 2016 at 22:47
  • 1
    $\begingroup$ @denesp Oh jeez ya oops. No idea why I wrote that. Too late to edit. Oh I guess I was thinking of needing the utility function to be continuous for sufficiency. $\endgroup$
    – VCG
    Commented Sep 11, 2016 at 22:53

2 Answers 2

7
$\begingroup$

Recall the definition:

The function $u: X \rightarrow \mathbb{R}$ represents $\succeq$ on $X$ if for any $x,y \in X$, then $x \succeq y \iff u(x) \geq u(y)$

We can show that if $u: X \rightarrow \mathbb{R}$ represents $\succeq$ on $X$, then for any strictly increasing function, $f: \mathbb{R} \rightarrow \mathbb{R}$, the function $v(x) = f(u(x))$ also represents $\succeq$

(Short) Proof: For any $x,y \in X$, if $u$ represents $\succeq$, then $x \succeq y \iff u(x) \geq u(y)$ by definition.

Because $v$ is strictly increasing, $f(u(x)) \geq f(u(y)), \implies v(x) \geq v(y)$.

Thus $x \succeq y \iff v(x) \geq v(y), \implies v$ represents $\succeq$


In your case, you have $u(x,y) = x^\frac{1}{3}y^\frac{1}{3}$, and can set $v(x, y) = (u(x,y))^9 = x^3y^3$, your desired result.

$\endgroup$
1
$\begingroup$

Another trick is to compare their marginal rate of substitution. If for a similar marginal rate of technical substitution (i.e. relative prices) they yield the same relative inputs, then they represent the same preferences (basically one is a monotonic transformation of the other; see below).

For the first preferences you give, this is:

$$ \frac{\dfrac{\partial u}{\partial x}}{\dfrac{\partial u}{\partial y}} = \frac{y}{x} $$

It is trivial to show that the second function yields the same MRS. Hence, they represent the same preferences.


Another way to look at this is to notice that optimising a function $f(x)$ is the same than optimising a monotonically transformation of such function. Thus, apply the natural logarithm to the two functions and you get, respectively:

$$ \ln u = \frac{1}{3}\left(\ln x + \ln y \right) $$

$$ \ln v = 3\left(\ln x + \ln y \right) $$

Notice that $\ln v = 9\ln u$. Hence, they are indeed the same.

$\endgroup$

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service and acknowledge you have read our privacy policy.

Not the answer you're looking for? Browse other questions tagged or ask your own question.