I believe your questions are:
Q1. Why is $\succ$ not symmetric?
Q2. Why is $\sim$ (a) symmetric; (b) reflexive; and (c) transitive?
Answers:
A1. Suppose $x \succ y$. Then by Definition 4 (refer to basic setup and definitions below), $x \succsim y$ and $y \not\succsim x$. Therefore, by the same definition, $y \not\succ x$. Thus, $\succ$ is not symmetric.
A2. Let $x,y,z\in X$.
A2(a)$\hspace{10pt}$ $x\sim y$ $\hspace{10pt}$ $\iff$ $\hspace{10pt}$$x\succsim y$ and $y\succsim x$ (Definition 3) $\hspace{10pt}$ $\iff$ $\hspace{10pt}$$y\sim x$.
A2(b) By Definition 2, $x \succsim x$. And so, by Definition 3, $x \sim x$.
A2(c) Suppose $x\sim y$ and $y\sim z$. (We will show that $x\sim z$.)
By Definition 2, we have $x\succsim y$ and $y\succsim z$. And now by the transitivity of $\succsim$, we have $x\overset{1}{\succsim} z$.
Similarly, we also have $y\succsim x$ and $z\succsim y$. And so again by the transitivity of $\succsim$, we have $z\overset{2}{\succsim} x$.
Given $\overset{1}{\succsim}$ and $\overset{2}{\succsim}$, by Definition 3, we have $x\sim z$.
Basic setup and definitions.
Definition 1. A (binary) relation $R$ (on a set $X$) is:
Symmetric if for all $x,y\in X$, $xRy \iff yRx$;
Reflexive if for all $x\in X$, $xRx$;
Transitive if for all $x,y,z\in X$, $xRy$ and $yRz$ implies $xRz$.
Let $X$ be our set of alternatives.
Definition 2. Let $\succsim$ be a reflexive and transitive relation on $X$.
We interpret $\succsim$ as the weakly-preferred-to relation.
Definition 3. $x \sim y$ if $x \succsim y$ and $y \succsim x$.
We interpret $\sim$ as the indifference relation.
Definition 4. $x \succ y$ if $x \succsim y$ and $y \not\succsim x$.
We interpret $\succ$ as the strictly-preferred-to relation.