The locus of kinks would follow x=y^2 but what would the arms look like?

  • 1
    $\begingroup$ Consider $\min \{\sqrt{x},y\}=k$ for various values of $k$. $\endgroup$ – Kenny LJ Sep 9 '19 at 5:09
  • 2
    $\begingroup$ What have you tried to figure this out? $\endgroup$ – Giskard Sep 9 '19 at 8:04
  • $\begingroup$ @Giskard I started with finding out the locus of the kinks by taking √x = y. Then I took y=k and √x = k to find the arms of the IC but I was confused about the √x = k arm. I thought that it will be a non - linear arm but the answer below by Amit clarifies the confusion $\endgroup$ – Kautilya Sep 9 '19 at 18:42

This is how indifference curves look : enter image description here

| improve this answer | |

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Not the answer you're looking for? Browse other questions tagged or ask your own question.