The locus of kinks would follow x=y^2 but what would the arms look like?

  • 1
    $\begingroup$ Consider $\min \{\sqrt{x},y\}=k$ for various values of $k$. $\endgroup$
    – user18
    Sep 9 '19 at 5:09
  • 2
    $\begingroup$ What have you tried to figure this out? $\endgroup$
    – Giskard
    Sep 9 '19 at 8:04
  • $\begingroup$ @Giskard I started with finding out the locus of the kinks by taking √x = y. Then I took y=k and √x = k to find the arms of the IC but I was confused about the √x = k arm. I thought that it will be a non - linear arm but the answer below by Amit clarifies the confusion $\endgroup$
    – Kautilya
    Sep 9 '19 at 18:42

This is how indifference curves look : enter image description here


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