# Mixed dominance game theory

I don't quite understand here, how exactly is the strategy $$(\sigma_1(U),\sigma(M),\sigma_1(D))=(0,1/2,1/2)$$ dominates $$U$$ since if you look at the first column, $$5$$ is greates than $$3/2+4/2=1.5+2=3.5$$ . I'm guessing i'm doing something wrong. Could someone please tell me what i'm doing/thinking wrong?

The text says domination is "in the game remaining after one stage of elimination".

In stage one, column L can be eliminated. As this is exercise b., I am guessing that was exercise a.