# Maximum of conditional expectation

I have a statistics question for the insider problem in the Kyle (1985) model:

How does one go from

$$\max\limits_{X} E[(v-\bar{v}-\lambda(X+u))X|v]$$

to

$$\max\limits_{X} (v-\bar{v}-\lambda X)X$$ ?

• Probably because $E(u \mid v )=0$. – Herr K. Apr 23 at 12:18
• That makes sense, thanks. – user918814 Apr 23 at 12:26