1
$\begingroup$

In a regression model estimated with $n$ observations, $$y_i = \beta_0 +\beta_1 x_{1i}+...+\beta_k x_{ki} +u_i$$ the baseline degrees of freedom adjustment when calculating standard errors is to multiply the squared residuals, $\hat{u_i}^2$, by $\frac{n}{n-k-1}$. I know the derivation for this.

Suppose there is clustering with $G$ groups for which $Cov(u_i,u_j)\ne 0$ if and only if $i$ and $j$ are in the same group. Let $\hat{u_g}$ denote the column vector of residuals from group $g$. The degrees of freedom adjustment is to multiply $\hat{u_g}\hat{u_g}'$ by $\frac{n-1}{n-k-1} \frac{G}{G-1}$. I know this result (Green's Econometric Analysis presents this without proof), but I have not seen a derivation for it.

I am hoping for either a derivation of that adjustment or a reference to a derivation.

$\endgroup$

0

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service and acknowledge that you have read and understand our privacy policy and code of conduct.

Browse other questions tagged or ask your own question.