The question I'm dealing with:
Let $x=3$, find any Nash equilibrium in pure or mixed strategies.
I have observed that the pure strategy Nash equilibrium is $(u,r)=(3,3)$.
The answer to this question is:
Am I correct in interpreting the above as:
Given the PSNE of $(u,r)$, the row player will play $u$ with probability $1$ and the column player will play $r$ with probability $1-0=1$?