# What's the point of keeping impossible strategies in strategy space?

Question from Strategy by Joel Watson:

I understand that the answer should be "not hire is not a strategy" but I don't see the problem with it being one. What's the point of keeping {NFF', NFR', NRF', NRR'} in Manager's strategy space instead of just N when we know that NFF' etc. cannot happen anyway? Isn't it inefficient in terms of storage too? I read the author's explanation:

One reason for this is that our study of rationality will explicitly require the evaluation of players’ optimal moves starting from arbitrary points in a game. This evaluation is connected to the beliefs that players have about each other. For example, in the game depicted in Figure 3.1(b), player l’s optimal choice at his first information set depends on what he thinks player 2 would do if put on the move. Furthermore, to select the best course of action, perspicacious player 2 must consider what player 1 would do at his second information set. Thus, player 2 must form a belief about player l’s action at the third node. A belief is a conjecture about what strategy the other player is using; therefore, player l’s strategy must include a prescription for his second information set, regardless of what this strategy prescribes for his first information set.

But NFF' is not even an "arbitrary point" in the game. Can anyone explain why keep 4 instead of 1 element in the strategy space in this case?

• Does this answer your question? When action and strategy differ in game theory Commented Oct 3, 2022 at 19:24
• NF', NF, NR, and NR' are not strategies of the Manager. These should be NFF', NFR', NRF', and NRR'. Commented Oct 4, 2022 at 10:57
• @VARulle thanks for the correction. Fixed it. Commented Oct 10, 2022 at 8:37