I'm trying to solve the following excercise:
Find the contract curve for an economy where agents' ($A$ and $B$) preferences and endowments are given by:
$u_A = x_{1A}^{\frac{1}{2}} x_{2A}^{\frac{1}{2}}$
$u_B = \min\{x_{1B},x_{2B}\}$
$(\omega_{1A},\omega_{2A}) = (\alpha,\beta)$
$(\omega_{1B},\omega_{2B}) = (\beta,\alpha)$
I know the contract curve in this case can be found by solving:
- $\max x_{1A}^{\frac{1}{2}} x_{2A}^{\frac{1}{2}}$
subject to
$ \min \{x_{1B},x_{2B}\} = \overline{U}$
$x_{1A} + x_{1B} = \alpha + \beta$
$x_{2A} + x_{2B} = \alpha + \beta$
or by solving
- $\max \min\{x_{1B},x_{2B}\}$ $(0)$
subject to
$x_{1A}^{\frac{1}{2}} x_{2A}^{\frac{1}{2}} = \overline{U}$ $(1)$
$x_{1A} + x_{1B} = \alpha + \beta$ $(2)$
$x_{2A} + x_{2B} = \alpha + \beta$ $(3)$
I know the usual ways to find contract curves are either by forming a Lagrangian or as a shortcut, start from solving $MRS_A = MRS_B$.
However, the presence of a Leontief function makes either of these problems unsolvable through methods involving differentiability (Lagrangian or MRS shortcut).
I think the latter problem is the easier one, I'd start by setting $x_{1B} = x_{2B}$ as the standard procedure for solving a constrained Leontief optimization problem (equation $(0)$).
I know equation $x_{1B} = x_{2B}$ is a valid equation for a contract curve. Is this already the contract curve?
What I found weird is I got a valid equation for a contract curve without even using the constraints $(1)-(3)$.
If it isn't the contract curve, I wouldn't know how to use equation $(1)$ involving $A$'s utility.