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I just say Amit's comment on this question: The second welfare theorem without monotonicity so I got curious and tried to find both the contract curve for that particular problem, and the Walrasian equilibria when both agents have the endowments $(w_x,w_y)=(2,2)$.

The problem regarding Amit's comment is

$u_i(x_i,y_i) = - (x_i-1)^2 - (y_i-1)^2$

$w_x = 4$

$w_y = 4$

Since the utility function (in this case the same one for both agents) is differentiable everywhere and non linear, using $MRS_1 = MRS_2$ and the endowment constraints gives me the contract curve. Doing this procedure I got that the contract curve is $y_1 = x_1$.

Clearly the allocation $((x_1,y_1),(x_2,y_2)) = ((2,2),(2,2))$ belongs to the contract curve.

However, Amit said in his comment that the alocation $((x_1,y_1),(x_2,y_2)) = ((2,2),(2,2))$ is not a competitive equilibrium.

My curiosity led me to do the experiment of trying to find the Walrasian Equilibrium for the problem above, given the endowments as the allocation $((w_{x1},w_{y1}),(w_{x2},w_{y2})) = ((2,2),(2,2))$.

I started computing the consumers' demands as usual.

Since both consumers have the same utility function and endowments, solving this optimization problem would yield me the demand functions for both consumers:

$\max -(x-1)^2-(y-1)^2$

s.t. $p_x x + p_y y = 2 p_x + 2 p_y$

Using the $MRS = \frac{p_x}{p_y}$ shortcut,

$\frac{\frac{\partial u_i}{\partial x}}{\frac{\partial u_i}{\partial y}} = \frac{p_x}{p_y} \implies \frac{-2 (x-1)}{-2(y-1)} = \frac{p_x}{p_y} \implies \frac{x-1}{y-1} = \frac{p_x}{p_y} \implies x-1 = \frac{p_x}{p_y}(y-1) \implies x = \frac{p_x}{p_y} (y-1) + 1$

$\implies x = \frac{p_x}{p_y} y - \frac{p_x}{p_y} + 1$

Plugging this expression for $x$ into the budget constraint,

$p_x (\frac{p_x}{p_y} y - \frac{p_x}{p_y} + 1) + p_y y = 2 p_x + 2 p_y \implies \frac{{p_x}^2}{p_y} y - \frac{{p_x}^2}{p_y} + p_x + p_y y = 2 p_x + 2 p_y$

$\implies (\frac{{p_x}^2}{p_y} + p_y) y = 2 p_x + 2 p_y + \frac{{p_x}^2}{p_y} - p_x \implies y = \frac{2 p_x + 2 p_y + \frac{{p_x}^2}{p_y} - p_x}{\frac{{p_x}^2}{p_y} + p_y}$

For simplicity let's take as numeraire $p_y = 1$

$\implies y = \frac{2 p_x + 2 + {p_x}^2 - p_x}{{p_x}^2 + 1}$

Simplifying to get the demands for good $y$

${y_1}^\star = {y_2}^\star = \frac{{p_x}^2 + p_x + 2}{{p_x}^2 + 1}$

The previous expression for $x$ after taking into account $p_y = 1$ is the numeraire becomes

$x = p_x y - p_x + 1$

Substituting the demand for $y$ into this expression

$\implies x = p_x (\frac{{p_x}^2 + p_x + 2}{{p_x}^2 + 1} - 1) + 1 \implies x = p_x \cdot \frac{{p_x}^2 + p_x + 2 - {p_x}^2 - 1}{{p_x}^2 + 1} + 1 \implies x = p_x \cdot \frac{p_x + 1}{{p_x}^2 + 1} + 1 \implies x = \frac{{p_x}^2 + p_x + {p_x}^2 + 1}{{p_x}^2 + 1} \implies {x_1}^\star = {x_2}^\star = \frac{2 {p_x}^2 + p_x + 1}{{p_x}^2 + 1}$

The equilibrium condition on good $y$ is

${y_1}^\star + {y_2}^\star = 4 \implies 2 \cdot \frac{{p_x}^2 + p_x + 2}{{p_x}^2 + 1} = 4 \implies \frac{{p_x}^2 + p_x + 2}{{p_x}^2 + 1} = 2 \implies {p_x}^2 + p_x + 2 = 2 {p_x}^2 + 2 \implies p_x = {p_x}^2$

$\implies {p_x}^2 - p_x = 0 \implies p_x (p_x - 1) = 0$

From here we get $p_x = 1$ or $p_x = 0$.

Substituting $p_x = 0$ into the equilibrium condition for good $x$ yields a contradiction, while $p_x = 1$ works.

Therefore, ${p_x}^\star = 1$ is the only equilibrium relative price.

Substituting ${p_x}^\star = 1$ into each demand function yields the allocation $((x_1,y_1),(x_2,y_2)) = ((2,2),(2,2))$

This would imply that $((x_1,y_1),(x_2,y_2)) = ((2,2),(2,2))$ is the equilibrium allocation supported by the relative prices $\frac{{p_x}^\star}{{p_y}^\star} = 1$, contradicting Amit's comment.

Is it wrong to apply any of the usual methods for non monotonic utility functions?

I plotted the situation on GeoGebra, which makes it seem like my results are correct:

enter image description here

Geogebra's axes: Agent A's axes

Orange axes: Agent B's axes

Purple line: Contract curve

Blue points: Bliss point for each agent, as the labels say

Red circle: A's indifference curve

Black circle: B's indifference curve

Green line: Price line $\frac{{p_x}^\star}{{p_y}^\star} = 1$, passing through the allocation $((x_1,y_1),(x_2,y_2)) = ((2,2),(2,2))$, which is indeed tangent to both agents' indifference curves.

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1 Answer 1

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Set of Pareto efficient allocations (or contract curve) is the set of all feasible allocations satisfying $1 \leq x_1=y_1\leq 3$. This is the line segment connecting points A and B in your graph.

Also, given the prices $(p_X^*, p_Y^*)=(1,1)$, and endowment $((2,2),(2,2))$, the budget constraint of the consumers is $p_X^*x_i+p_Y^*y_i\leq 2+2=4$, and therefore, consumers will demand their bliss points i.e. both will demand the bundle $(1,1)$ and $((2,2),(2,2))$ is not a competitive equilibrium allocation.

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  • $\begingroup$ thank you for the answer! $\endgroup$ Apr 10 at 6:21
  • $\begingroup$ Does the fact that the aggregate of consumers' demands doesn't equal the total endowment here imply this problem given the specific endowments, has no Walrasian Equilibrium? $\endgroup$ Apr 10 at 6:23
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    $\begingroup$ Yes, this video has the definition of competitive (or Walrasian) equilibrium that I have used to answer this question: youtu.be/7U3LpSx2KCE $\endgroup$
    – Amit
    Apr 10 at 6:31
  • $\begingroup$ I just checked and it was clear for me why the points where $x_1 < 1$ and $x_1 > 3$ are not Pareto efficient. Is the systematic way to find the CC for non-monotonic (differentiable and non-linear) utilities is to always do the usual $MRS$ procedure and then check by cases? $\endgroup$ Apr 10 at 6:36
  • $\begingroup$ Thank you! I will check the video now and see if I got it. $\endgroup$ Apr 10 at 6:37

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