Is there any difference between solving the social planner's problem or the representative household's in the Ramsey-Cass-Koopmans model?
The social planner chooses a plan $\left\{c_t, l_t, k_{t+1}\right\}_{t=0}^{\infty}$ so as to maximize utility subject to the resource constraint of the economy, taking initial $k_0$ as given: $$ \begin{gathered} \max \mathcal{U}_0=\sum_{t=0}^{\infty} \beta^t U\left(c_t, 1-l_t\right) \\ c_t+k_{t+1} \leq(1-\delta) k_t+F\left(k_t, l_t\right), \quad \forall t \geq 0 \\ c_t \geq 0, \quad l_t \in[0,1], \quad k_{t+1} \geq 0 ., \quad \forall t \geq 0 \\ k_0>0 \text { given } \end{gathered} $$ This is called the social planner's problem.
Given a price sequence $\left\{R_t, w_t\right\}_{t=0}^{\infty}$, household $j$ chooses a plan $\left\{c_t^j, l_t^j, k_{t+1}^j\right\}_{t=0}^{\infty}$ so as to maximize lifetime utility subject to its budget constraints $$ \begin{gathered} \max \mathcal{U}_0^j=\sum_{t=0}^{\infty} \beta^t U\left(c_t^j, 1-l_t^j\right) \\ \text { s.t. } c_t^j+a_{t+1}^j \leq\left(1+R_t\right) a_t^j+w_t l_t^j \\ c_t^j \geq 0, \quad l_t^j \in[0,1], \quad a_{t+1}^j \geq \underline{a}_{t+1} \end{gathered} $$ This is called the household's problem.