Hey guys I need your help to solve the following problem. Here's my attempt.
Given the function: $$u(x_1,x_2)=x_1+x_2^\beta, \ \ \beta \in (0,1).$$
- Write down the UMP and solve for the Walrasian Demands of $x_1, x_2$.
- Is good 1 a Normal good? And good 2?
- Compute the indirect utility function for this problem and show that it can be written as $v(w,\mathbf{p})=\tilde{v}(w,p_1)$.
My attempt: $$\mathcal{L}(\mathbf{x},\lambda)=x_1+x_2^\beta-\lambda(p_1x_1+p_2x_2-w).$$ $$\frac{\partial\mathcal{L}}{\partial x_1}=1-\lambda p_1 = 0.$$ $$\frac{\partial\mathcal{L}}{\partial x_2}=\beta x_2^{(\beta - 1)}-\lambda p_2 = 0$$ $$\frac{\partial\mathcal{L}}{\partial \lambda}=p_1x_1+p_2x_2=w$$ By solving the system I end up with: $$x_1^*(\mathbf{p},w)=\frac{w}{p_1}-(\frac{p_2}{p_1})^{\frac{\beta}{\beta -1}}\cdot \frac{1}{\beta^{\frac{1}{\beta - 1}}} \\ x_2^*(\mathbf{p},w)=(\frac{p_2}{\beta p_1})^{\frac{1}{\beta -1}}$$ A good is defined normal if $\frac{\partial x_i^*}{\partial w} > 0.$ $$\frac{\partial x_1^*}{\partial w} = \frac{1}{p_1} > 0.$$ Good 1 is a normal good. Good 2 is not a function of $w$, implying that $x_2$ is a neutral good.
Indirect utility function: $$v(\mathbf{p},w) \equiv u(x_1^*,x_2^*) $$ $$v(\mathbf{p},w)= \frac{w}{p_1}-(\frac{p_2}{p_1})^{\frac{\beta}{\beta -1}}\cdot \frac{1}{\beta^{\frac{1}{\beta - 1}}}+((\frac{p_2}{\beta p_1})^{\frac{1}{\beta -1}})^\beta .$$ The indirect utility function is function of both $p_1,p_2$, how can I show that is function of $p_1$ only?