The passage quoted is (at least) sloppy as regards language, in that it writes first "relatively less expensive", and then uses "even more", which would be correct if previously it had described a "more" expensive rather than a "less" expensive situation.
What happens here is that, under the assumption that Purchasing Power Parity holds (or tends to hold), we have
$$\pi = \pi^* - \dot S/S$$
Where $\pi$ is local inflation, $\pi^*$ is "foreign" inflation, and $\dot S/S$ is the growth rate of "local" exchange rate (units of foreign currency per unit of local currency).
Then, if $\pi > \pi^* \implies \dot S/S <0 \implies \dot S <0$, at least as a tendency, and the local currency will, eventually, depreciate.
For clarity, assume that we start from a situation where both inflation rates are zero. Then, local positive inflation happens, for some local reason.
Initially, before the exchange rate starts to adjust, local exports become more expensive for the foreigners (as the answer by @user3522240 describes), while imports (whose nominal price in terms of foreign currency has not changed, due to zero foreign inflation) become relatively less expensive, with "relatively" referring to the relative contribution of imported resources to local costs of production, compared to the cost of local resources. Imports do not become "cheaper" in nominal terms, in either currency. Only their percentage contribution to total costs becomes smaller.
But since eventually, we assume that the exchange rate will depreciate, weakening the local currency, the nominal cost of imports in terms of local currency will increase. But this will now increase the total cost of production in terms of local currency, and it will tend to add inflation to the already existing, locally generated, inflation rate, as firms will attempt to pass this imports-linked increase in costs to consumers.
APPENDIX
The Purchasing Power Parity in terms of inflation rates is derived as follows: Denote $P$ the local price level and $P^*$ the foreign price level. Then PPP is expressed as
$$P\cdot S = P^*$$
Differentiate with respect to time,
$$\dot PS + P\dot S = \dot P^*$$
Manipulate (and use the PPP relation)
$$\implies \frac {\dot P}{P}S + \frac {P}{P}\dot S = \frac {\dot P^*}{P^*}\frac {P^*}{P} \implies \pi S + \dot S = \pi^* S$$
Divide by $S$ and re-arrange to obtain
$$\pi = \pi^* - \dot S/S$$