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ln(Q) = 10-0.7ln(P), where P is price and Q is demand.

What is the price elasticity of demand?

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closed as off-topic by BKay, Lumi, cc7768, FooBar, EnergyNumbers Aug 20 '15 at 19:19

This question appears to be off-topic. The users who voted to close gave this specific reason:

  • "This question does not appear to be about economics, within the scope defined in the help center." – BKay, Lumi, cc7768, FooBar, EnergyNumbers
If this question can be reworded to fit the rules in the help center, please edit the question.

  • $\begingroup$ This question has been put on hold by the community as it appears to be a homework question with no individual effort shown. $\endgroup$ – Ubiquitous Aug 21 '15 at 7:43
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Did you know you can write price elasticity $\varepsilon$ as $\varepsilon \equiv \frac{d \log Q}{d \log P}$?

(Indeed, $\frac{d \log Q}{d \log P} =\frac{dQ}{dP} \frac{P}{Q}$. Check out wiki on elasticity of a function if you want more detail!)

Using this "log notation" for elasticity, it is easy to see without putting pen to paper that in this example, $\varepsilon = -0.7$.

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The price elacitiy of demand is $\frac{\partial Q}{\partial P}\cdot \frac{P}{Q(P)}$. To get Q(P) you have to write both sides of the equations as an exponent of the base e.

$$ e^{ln(Q)}=e^{10-0.7ln(P)} $$

$$ Q=e^{10}\cdot e^{-0.7ln(P)}\Rightarrow Q= e^{10}\cdot \left(e^{ln(P)}\right)^{-0.7}$$

$$Q(P)=e^{10}\cdot p^{-0.7} $$

Therfore

$$ \frac{\partial Q}{\partial P}=e^{10}\cdot (-0.7)\cdot p^{-1.7}$$

I think you can take it from here. If not, feel free to ask.

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