How to find the mixed strategy equilibrium in the following game:
P2 L R L (3,1) (0,1) P1 M (1,1) (1,1) R (0,1) (4,1)
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As you have suggested in a comment, $M$ will not be played with positive probability in any Nash equilibrium. This is true for any strictly dominated action.
Given that $M$ has zero probability, the rest of your question is answered in another question of yours in another thread at How infinite Nash equilibria are possible in a game?