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Is there a term for a game whose pareto optimal solutions and nash equilibria are disjoint?

(e.g. prisoner's dilemma)

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The term I often come across is 'inefficient Nash equilibrium' or 'Pareto-inefficient Nash equilibrium'. Here is an older well cited article discussing inefficient NEs: http://www.jstor.org/stable/3690047?seq=1#page_scan_tab_contents

Here is the frequency of the term 'inefficient Nash equilibrium' used in scientific papers: https://scholar.google.com/scholar?q=%22Inefficient+Nash+Equilibrium%22&btnG=&hl=en&as_sdt=0%2C5

'Inefficient outcome' is also frequently used to describe NEs that are not Pareto-optimal: https://scholar.google.com/scholar?q=%22Inefficient+outcome%22&btnG=&hl=en&as_sdt=0%2C5 But it has to be put into game-theoretical context and specified that it is NE.

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    $\begingroup$ I think these terms do not quite fit. A single Nash equilibrium may be inefficient, but another Nash equilibrium may not be, in which case the two sets are not disjoint. $\endgroup$ – HRSE Dec 1 '15 at 2:30
  • $\begingroup$ @HRSE I agree. It would make sense only for a game with either one NE (like prisoner's dilemma) or many NE's, all of which are inefficient. So maybe there is a room for a better answer if anyone came across anything more specific. $\endgroup$ – Arthur Tarasov Dec 1 '15 at 2:41
  • $\begingroup$ I propose that we begin referring to such games as exhibiting the "user2429920 property" $\endgroup$ – John Q. Noob May 16 '16 at 19:37
  • $\begingroup$ I propose "inefficient game". Thoughts? $\endgroup$ – capybaralet Jun 8 '16 at 4:26

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