Define a Bayesian game as follows: $$G = \left\langle I, \left(A_i,T_i,(p_{t_i})_{t_i \in T_i}, u_i \right)_{i \in I} \right\rangle$$
- $I$ is the set of players
- $A_i$ is the action set for player $i$,
- $T_i$ is the set of possible types for player $i$,
- $p_{t_i} \in \Delta(T_{-i})$ is player $i$'s beliefs regarding the types of the other players. $(T_{-i}=\times_{j \ne i}T_j)$
- $u_i : A \times T \rightarrow \mathbb{R}$ is player $i$'s utility function
Then a Bayes-Nash equilibrium is defined as follows:
A (pure) Bayes-Nash equilibrium is a profile of choice functions (or strategies) $(\sigma_i:T_i \rightarrow A_i)_{i \in I}$ such that, $\forall i \in I, \forall t_i \in T_i, \forall a_i \in A_i$,
$$\sum_{t_-{i}}p_{t_i}(t_{-i}) \cdot u_i(\sigma_i(t_i), \sigma_{-i}(t_{-i}); t_i, t_{-i}) \geq \sum_{t_-{i}}p_{t_i}(t_{-i}) \cdot u_i(a_i, \sigma_{-i}(t_{-i}); t_i, t_{-i}) $$ where, for every $t_{-i}, \sigma_{-i}(t_{-i}) = (\sigma_j(t_j))_{j\ne i}$.
And now my question: Am I correct that this implies that, in a BNE, every player (or rather, every type of every player) best responds given their beliefs about the types of other players, but that there is nothing in a BNE that pins down the beliefs a player (or type of player) has on the types of other players? That is to say, in a BNE, a player (or type of player) could have a degenerate belief (putting full probability on some $t_j^*$ for player $j$) in an equilibrium in which $t_j \ne t_j^*$? Put more simply, can a type of player's beliefs about the type of another player be wrong in a BNE?
there is nothing in a BNE that pins down the beliefs a player (or type of player) has on the types of other players
. $p_{t_i}$ pins down player $i$'s belief completely, as part of the definition of BNE. What's the problem there? $\endgroup$