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You got to the quadratic equation $$ \lambda^2 - (\rho - n)\lambda + \frac{c^\ast f''(k^\ast)}{\varepsilon} $$ The discriminant is given by: $$ \Delta = (\rho - n)^2 - 4 \frac{c^\ast f''(k^\ast)}{\varepsilon} $$ So the two roots are: $$ \lambda_1, \lambda_2 = \frac{(\rho - n) \pm \sqrt{(\rho - n)^2 - 4 \frac{c^\ast f''(k^\ast)}{2}}}{2} $$ As $f''(k) < 0$ ...


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