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Hint: Simply apply integration by parts to the integral on the LHS. Simplify and you should arrive at the following expression: \begin{equation} (1-R)-\int_{R-k}^1G(\theta)\mathrm d\theta. \end{equation} Add and subtract $k$ to obtain: \begin{equation} (1-R+k-k)-\int_{R-k}^1G(\theta)\mathrm d\theta = (1-(R-k))-k-\int_{R-k}^1G(\theta)\mathrm d\theta. \end{...


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