# Tag Info

Hint: Simply apply integration by parts to the integral on the LHS. Simplify and you should arrive at the following expression: $$(1-R)-\int_{R-k}^1G(\theta)\mathrm d\theta.$$ Add and subtract $k$ to obtain: (1-R+k-k)-\int_{R-k}^1G(\theta)\mathrm d\theta = (1-(R-k))-k-\int_{R-k}^1G(\theta)\mathrm d\theta. \end{...