# Are there Nash Equilibria that aren't mixed strategies?

We can consider only finite games if it makes a difference, but are there nash equilibria that can't be characterized as mixed equilibria?

• I find this question either unclear or trivial. Please include your exact definitions. – Giskard Mar 9 '18 at 20:00
• The example that immediately comes to mind is prisoner's dilemma: the Nash equilibrium is for both players to pick "betray". – alexgbelov Mar 14 '18 at 23:48

That is, it is a mixed strategy in which a pure strategy is played with probability $1$.