0
$\begingroup$

Suppose there are two people living together. They have the same utility function (CES) $$u(x,h)=(x^\rho+h^\rho)^\frac{1}{\rho}$$ where $x$ is a type of good, $h$ is housing. The price of good is $p$, the unit of rent is $r$. Their income is both $w$. The maximization problem is (if I have it correctly) \begin{align*} &\max u(x_1,h)+u(x_2,h)\\ &\text{s.t. }x_1p+x_2p+rh=2w \end{align*} I want to determine how $\rho$ affects the per capita consumption of the $x$. Since there are 3 goods in this model, I'm finding it difficult to start. Any ideas are appreciated.

$\endgroup$

1 Answer 1

1
$\begingroup$

Given the great amount of symmetry in your problem, it can actually be reduced to a problem in only two variables. Let us first show that in the optimum $x_1 = x_2$. Towards a contradiction, assume that $(x_1, x_2, h)$ is optimal but $x_1 \ne x_2$.

Consider the allocation $(\tilde x, \tilde x, h)$ where $\tilde x = \frac{x_1 + x_2}{2}$. This bundle is feasible: $$ p \tilde x + p \tilde x + r h = p x_1 + p x_2 + rh \le 2w. $$

Also, by strict concavity of $u(x,h)$, we have: $$ u(\tilde x, h) + u(\tilde x, h) > \frac{1}{2} u(x_1,h) + \frac{1}{2} u(x_2,h) + \frac{1}{2} u(x_1,h) + \frac{1}{2} u(x_2,h) = u(x_1, h) + u(x_2,h), $$ which contradicts optimality of $(x_1, x_2, h)$.

Now, given that $x_1 = x_2$ in the optimum, we can rewrite the optimisation problem as: $$ \max_{x,h} 2 u(x,h) \text{ s.t. } 2p x + rh \le 2w. $$ The factor of 2 in the objective function can be ignored as it will not change the solution of this maximisation problem. As such, the optimal bundle will be given by the usual demands for a CES utility function where the prices are $2p$ and $r$ and the income level is $2w$.

$\endgroup$

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service and acknowledge you have read our privacy policy.

Not the answer you're looking for? Browse other questions tagged or ask your own question.